전자기학

최근 수정: 27/06/2024, 23:25:45

D=ρfB=0×E=Bt×H=Jf+Dt\begin{aligned}
\boldsymbol{\nabla} \boldsymbol{\cdot} \mathbf{D} &= \rho_f \\
\boldsymbol{\nabla} \boldsymbol{\cdot} \mathbf{B} &= 0 \\
\boldsymbol{\nabla} \times \mathbf{E} &= -\frac{\partial \mathbf{B}}{\partial t} \\
\boldsymbol{\nabla} \times \mathbf{H} &= \mathbf{J}_f + \frac{\partial \mathbf{D}}{\partial t}
\end{aligned}